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解决在bv号内的C语言实例线程不安全的问题 (#119)

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原示例使用全局变量`char result[13]`, 多线程中同时调用av2bv可能导致结果出错
现改为在堆内存上进行操作以及返回, 由caller来free
This commit is contained in:
Executor
2020-12-29 11:15:37 +08:00
committed by GitHub
parent 610a5ca803
commit 27a5968ebc
1 changed files with 3 additions and 3 deletions
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6
other/bvID.md
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@@ -101,6 +101,7 @@ BV17x411w7KC
```c ```c
#include <stdio.h> #include <stdio.h>
#include <stdlib.h>
#include <math.h> #include <math.h>
#include <string.h> #include <string.h>
@@ -109,7 +110,6 @@ char tr[124]; //反查码表
const unsigned long long Xor = 177451812; //固定异或值 const unsigned long long Xor = 177451812; //固定异或值
const unsigned long long add = 8728348608; //固定加法值 const unsigned long long add = 8728348608; //固定加法值
const int s[] = {11, 10, 3, 8, 4, 6}; //位置编码表 const int s[] = {11, 10, 3, 8, 4, 6}; //位置编码表
char result[13]; //编码结果
//初始化反查码表 //初始化反查码表
void tr_init() void tr_init()
@@ -130,12 +130,12 @@ unsigned long long bv2av(char bv[])
char* av2bv(unsigned long long av) char* av2bv(unsigned long long av)
{ {
char* result = (char*)malloc(13);
strcpy(result,"BV1 4 1 7 "); strcpy(result,"BV1 4 1 7 ");
av = (av ^ Xor) + add; av = (av ^ Xor) + add;
for (int i = 0; i < 6; i++) for (int i = 0; i < 6; i++)
result[s[i]] = table[(unsigned long long)(av / (unsigned long long)pow(58, i)) % 58]; result[s[i]] = table[(unsigned long long)(av / (unsigned long long)pow(58, i)) % 58];
char *bv=result; return result;
return bv;
} }
int main() int main()